By Prof. L. Kaliambos (Natural Philosopher in New Energy)

October 19, 2015

Lithium is an atom of the chemical element Lithium with symbol Li and atomic number 3. However unlike for hydrogen atom , a closed-form solution to the Schrödinger equation for the many-electron atoms like the lithium atom has not been found. So, under the invalid relativity (EXPERIMENTS REJECT RELATIVITY) various approximations, such as the Hartree–Fock method, could be used to estimate the ground state energies. Under these difficulties I published my paper "Spin-spin interactions of electrons and also of nucleons create atomic molecular end nuclear structures" (2008) by analysing carefully the electromagnetic interactions of two spinning electrons of opposite spin which give a simple formula for the solution of such ground state energies. Hence today it is well known that the correct electron configuration of Lithium should be given by **this correct image **including the following electron configuration: 1s^{2}2s^{1}

According to the “Ionization energies of the elements-WIKIPEDIA” we observe
that E_{1} = 5.39 eV, E_{2} = 75.6 eV, and E_{3} =
122.4 eV. For the explanation of the first ionization energy (E_{1} =
5.39 eV) due to the outer electron (2s^{1})
with n = 2 you can see my paper “Explanation of lithium ionizations”.

Whereas for calculating the summation of the second and third ionization energies

E = (75.6 +122.4) = 198 eV

which gives the ground
state energy of Lithium (Z = 3) you can see my paper published in Ind. J. Th.
Phys. (2008) entitled “ Spin-spin interactions of electrons and also of
nucleons create atomic molecular and nuclear structures”. (See it in “User Kaliambos”). In that paper I showed that the ground state energy (-E = - 198
eV) is the binding energy of the two
spinning electrons of opposite spin of the Li^{+} with n = 1 when
Z = 3. That is

-E = - 198 = (-27.21)Z^{2 }+(16.95)Z - 4.1

Since Z = 3 one gets

-E = (-27.2)3^{2} + (16.95)3 - 4.1 = -
122.4 + 244.8 - 50.84 + 4.1 = -198 eV

Historically, despite the enormous success of the Bohr model and the quantum mechanics of the Schrodinger equation based on the well-established laws of electromagnetism in explaining the principal features of the hydrogen spectrum and of other one-electron atomic systems, so far, under the abandonment of natural laws neither was able to provide a satisfactory explanation of the two-electron atoms. In atomic physics a two-electron atom is a quantum mechanical system consisting of one nucleus with a charge Ze and just two electrons. This is the first case of many-electron systems. The first few two-electron atoms are:

Z =1 : H^{- }hydrogen
anion. Z = 2 : He helium atom. Z = 3 : Li^{+} lithium
atom anion. Z = 4 : Be^{2+} beryllium ion. Z =
5 : B^{3+} boron.

Prior to the development of quantum mechanics, an atom with many electrons was portrayed like the solar system, with the electrons representing the planets circulating about the nuclear “sun”. In the solar system, the gravitational interaction between planets is quite small compared with that between any planet and the very massive sun; interplanetary interactions can, therefore, be treated as small perturbations.

However, In the helium atom with two electrons, the interaction energy between the two spinning electrons and between an electron and the nucleus are almost of the same magnitude, and a perturbation approach is inapplicable.

In 1925 the two young Dutch physicists Uhlenbeck and Goudsmit discovered the electron spin according to which the peripheral velocity of a spinning electron is greater than the speed of light. Since this discovery invalidates Einstein’s relativity it met much opposition by physicists including Pauli. Under the influence of Einstein’s invalid relativity physicists believed that in nature cannot exist velocities faster than the speed of light.(See my FASTER THAN LIGHT).

So great physicists like Pauli, Heisenberg, and Dirac abandoned the natural laws of electromagnetism in favor of wrong theories including qualitative approaches under an idea of symmetry properties between the two electrons of opposite spin which lead to many complications. Thus, in the “Helium atom-Wikipedia” one reads: “Unlike for hydrogen a closed form solution to the Schrodinger equation for the helium atom has not been found. However various approximations such as the Hartree-Fock method ,can be used to estimate the ground state energy and wave function of atoms”.

It is of interest to note
that in 1993 in Olympia of Greece I presented at the international conference
“Frontiers of fundamental physics” my paper “Impact of Maxwell’s equation of displacement current on electromagnetic laws and comparison of the Maxwellian waves with our model of dipolic particles ". The conference was organised by the natural philosophers M. Barone and F. Selleri, who gave me an award including a disc of the atomic philosopher Democritus, because in that conference I showed
that LAWS AND EXPERIMENTS INVALIDATE FIELDS AND RELATIVITY .
At the same time I tried to find not only the nuclear force and structure
but also the coupling of two electrons under the application of the abandoned
electromagnetic laws. For example in the well known photoelectric effect the
absorption of light contributed not only to the increase of the electron energy
but also to the increase of the electron mass because the particles of light
have mass m = hν/c^{2} .(
See my DISCOVERY OF PHOTON MASS ).

However the electron spin which gives a peripheral velocity greater than the speed of light cannot be affected by the photon absorption. Under this condition the electromagnetic force can be written as

F_{em }= F_{e}
- F_{m} .

Therefore in my research
the integration for calculating the mutual F_{em} led to the
following relation:

F_{em }= F_{e}
- F_{m} = Ke^{2}/r^{2} - (Ke^{2}/r^{4})(9h^{2}/16π^{2}m^{2}c^{2})

Of course for F_{e} =
F_{m} one gets the equilibrium separation r_{o }=
3h/4πmc = 578.8/10^{15} m.

That is, for r <
578.8/10^{15} m the two electrons of opposite spin exert an
attractive electromagnetic force, because the attractive F_{m} is
stronger than the repulsive F_{e} . Here F_{m }is
a spin-dependent force of short range. As a consequence this situation
provides the physical basis for understanding the pairing of two electrons
described qualitatively by the Pauli principle, which cannot be applied in the
simplest case of the deuteron in nuclear physics, because the binding energy
between the two spinning nucleons occurs when the spin is not opposite (S=0)
but parallel (S=1). According to the experiments in the case of two electrons
with antiparallel spin the presence of a very strong external magnetic field
gives parallel spin (S=1) with electric and magnetic repulsions given by

F_{em }=
F_{e} + F_{m}

So, according to the
well-established laws of electromagnetism after a detailed analysis of
paired electrons in two-electron atoms I concluded that at r <
578.8/10^{15} m a motional EMF produces vibrations of
paired electrons.

Unfortunately today many physicists in the absence of a detailed knowledge believe that the two electrons of two-electron atoms under the Coulomb repulsion between the electrons move not together as one particle but as separated particles possessing the two opposite points of the diameter of the orbit around the nucleus. In fact, the two electrons of opposite spin behave like one particle circulating about the nucleus under the rules of quantum mechanics forming two-electron orbitals in helium, beryllium etc. In my paper of 2008, I showed that the positive vibration energy (Ev) described in eV depends on the Ze charge of nucleus as

Ev = (16.95)Z - 4.1

Of course in the absence of such a vibration energy Ev it is well-known that the ground state energy E described in eV for two orbiting electrons could be given by the Bohr model as

E = (-27.2) Z^{2}.

So the combination of the energies of the Bohr model and the vibration energies due to the opposite spin of two electrons led to my discovery of the ground state energy of two-electron atoms given by

E = (-27.2) Z^{2} +
(16.95 )Z - 4.1

For example the laboratory
measurement of the ionization energy of H^{-} yields an energy of
the ground state E = - 14.35 eV. In this case since Z = 1 we
get E -27.2 + 16.95 - 4.1 = -14.35 eV. In the same way
writing for the helium Z = 2 we get

E = - 108.8 + 32.9 - 4.1 = -79.0 eV

which is equal to the
laboratory measurement. In the same way we can calculate the ground state
energies for the Z = 3 : Li^{+} ion.

The discovery of this simple formula based on the well-established laws of electromagnetism was the first fundamental equation for understanding the energies of many-electron atoms, while various theories based on qualitative symmetry properties lead to complications. For example in “Lithium atom-WIKIPEDIA” we read: “Similarly to the case of the helium atom, a closed-form solution to the Schrödinger equation for the lithium atom has not been found. However, various approximations, such as the Hartree–Fock method, can be used to estimate the ground state energy and wavefunction of the atom. Quantum defect is a value that describes the deviation from hydrogenic energy levels.”